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obtain the general solution of auxiliary equation y'' - 8y' + 17y =0 y(0)=4 y'(0)=-1
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did you find the characteristic solution
r^2 -8r + 17=0 r = 4+i , 4 - i
ok so far?
the general solution is y = e^(4x) (c1*cos x + c2*sinx)
here is a site that explains it http://www.sosmath.com/diffeq/second/constantcof/constantcof.html
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y(0)=4 y(0) = e^(4*0) ( c1 cos(0) + c2 sin(0)) = 1 ( c1 + 0 ) Therefore c1 = 4 now take the derivative (use product rule)
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