Question

Divide

Answer 1

sorry can it be more clear

Answer 2

x^1/2 over x^2/7

Answer 3

remember the property:
\[{1\over a^m}=a^{-m}\]
so,
\[{x^{1/2}\over x^{2/7}}=x^{1/2}\cdot x^{-2/7}\]
no, we use the property
\[a^m\cdot a^n=a^{m+n}\]
so,
\[x^{1/2}\cdot x^{-2/7}=x^{{1\over2}-{2\over7}}=\Large x^{3/14}\]

Answer 4

no negative but yea

Answer 5

what do you mean "no negative"?