Question

The unemployment rates for March in 2 similar sized towns are being compared.
Town 1: of 1508 employed, 405 were laid off
Town 2: of 1252 employed, 281 were laid off

A) Test if there is any difference in the lay off rates at 5% level. . Please help me decide the order of steps. EOV first then Average?????????

Ho:___________ .05 (2-tail)
Ha:___________ Reject if: pvalue<.05
conclusion:

b)is there diff in lay off rates, how large is difference??

Answer 1

town1 unemployed = \[{405\over1058}\times100=?\]
town2 unemployed = \[{281\over1252}\times100=?\]

Answer 2

26.86
22.44

Answer 3

I didn't multiply by 100 though thats new

Answer 4

what is EOV now??

Answer 5

when you multiply by 100, the result is in percentage

Answer 6

equality of variance

Answer 7

% ok yes right

Answer 8

your calculations seem erroneous

Answer 9

because its 1508, and you did 1058 for town 1 :)

Answer 10

ooh :P

Answer 11

but what I do not understand is how to use the F-test when there is just one information given.

Answer 12

\[H_0:\sigma_1^2=\sigma_2^2\]

Answer 13

can we find the \[\alpha\]

Answer 14

ok i see about the F test is rejected then.

Answer 15

yes it is .05

Answer 16

α=.05

Answer 17

this is exactly 5%

Answer 18

yes that is alpha.

Answer 19

you get \[\alpha=0.05\] for both?

Answer 20

in our class we only use .05 for alpha α.

Answer 21

but here we are required to find the alpha

Answer 22

?

Answer 23

alpha is always .05, i'm just unsure which program on the calculator ti it is?

Answer 24

use the T-tables to find the "t" value for equal variances

Answer 25

ok so this is equal. I was thinking it was UNequal?

Answer 26

we are using Null hypothesis
what is sigma for H0
and
what is sigma for Ha

Answer 27

so do i use Z then?
aghhh im lost these words al lmix together

Answer 28

0 and 1

Answer 29

we are trying to compare the "p" values with 0.05

Answer 30

so is lay off rates the average..
?

Answer 31

ok logically speaking,
\[p_1={405\over1508}=0.2686\\
p_2={281\over1252}=0.2244\\
p=|p_1-p_2|=0.0442<0.05
\]
so, we reject the null hypothesis
and the difference between the layoff rates = 0.0442=4.42%