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Mathematics 13 Online
OpenStudy (jack1):

Help please: Solve the following system of partial differential equations for u(x,y): ∂u/∂y=2xyu ∂u/∂x=(y^2+5)u

OpenStudy (jack1):

i understand differentials... just not when they're a point on a graph

OpenStudy (jack1):

@jim_thompson5910 hey guys @mathslover any ideas @Preetha pretty please...?

OpenStudy (jack1):

@kropot72 @Luis_Rivera guys would really love a hand if you could spare a few minutes...?

OpenStudy (anonymous):

so they are giving you two partial derivatives and asking you to find the original function with it?

OpenStudy (jack1):

yeah, they're asking us to solve it with respect to "u"

OpenStudy (anonymous):

so this would be like partial antiderivatives?

OpenStudy (jack1):

yep... with a twist: u is made up of both x and y

OpenStudy (jack1):

u's the point x,y on a graph, dunno whether it makes a difference but it's got me stumped

OpenStudy (anonymous):

looks to me like u is the function varying with x and y, not the point (x,y)

OpenStudy (jack1):

... that would make sense

OpenStudy (jack1):

still have no idea where to start though i can integrate each equation with respect to one thing, but that doesn't help

OpenStudy (anonymous):

try integrating ∂u/∂y=2xyu with respect to y and the other one with respect to x if you can I have almost no knowledge here, I haven't even taken multivariable calculus.

OpenStudy (jack1):

hmmm, so far i've got u(y) =e^(x*(y^2)) times a constant

OpenStudy (jack1):

and u(y) = e^( ( (y^2)/3) ) +5y ) times a constant

OpenStudy (anonymous):

might this help? http://tutorial.math.lamar.edu/Classes/CalcIII/Differentials.aspx

OpenStudy (jack1):

cheers man, i think that page clears up a lot

OpenStudy (anonymous):

good :) but you really figured it out yourself.

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