Question

How do you find the exact value of sin(cot^-1 (5/4))?

Answer 1

cot^-1(5/4)=x
cotx=5/4
cosx/sinx=5/4
cos^2(x)+sin^2(x)=1
sinx=4/sqrt41

Answer 2

Thank you. Could you explain the part after cosx/sinx=5/4 ?I'm not really following it.

Answer 3

cotx=cosx/sinx did you know that?

Answer 4

I know that cotx=cosx/sinx, I just wasn't really following on what you did after that.

Answer 5

cos^2 x+sin^2 x=1
cosx=5m and sinx=4m

25m^2+16m^2=1
41m^2=1
m=1/sqrt41 so sinx=4m=4/sqrt41

do you understand now?

Answer 6

Yes, that makes more sense. Thank you.

Answer 7

welcome. if i could help, i'm so happy :)