Question

please help
photo attacahed!

Answer 1

du= x^2 and u =ex^3dx??

Answer 2

@Dodo1
take x^3=t
on differentiation
3x^2*dx=dt that is x^2*dx=dt/3
so ur Q now is integration( e^t*dt/3)
now u can solve it????

Answer 3

I am confused...
I thought I need to find out du and u first in order to find out the answer

Answer 4

notice that we can substitute \[u=x^3\]
when we make this substitution, we have to get rid of all "x" and have only "u" in our integral..
so, the second term becomes: \(\Large e^{x^3}=e^u\)
then we have to convert "dx" to "du". so, we differentiate the sustitution
\[u=x^3\implies{du\over dx}=3x^2\implies{du\over 3}=x^2dx\]
we already have "x^2dx" in the integral
so, our integral simplifies to
\[\int e^u{du\over 3}={1\over3}\int e^udu\\\quad
={1\over3}e^u+C
\]
we now replace "u" back with "x"
so, the integration becomes \[\Large \int x^2e^{x^3}dx={1\over3}e^{x^3}+C\]

Answer 5

I entred the answer and it tells me that it was wrong

Answer 6

it says Evaluate the indefinite integral.

Answer 7

@electrokid

Answer 8

did you put the "+C" and the fraction correctly?

Answer 9

Yes I have

Answer 10

@electrokid

Answer 11

it is
e^{x^3}
not
e^{x*3}

Answer 12

look at the substitution above

Answer 13

ops. thank you so much it worked!