Question

Anyone able to help me with solving right triangles?

Answer 1

I try..

Answer 2

I'm trying to figure out how to solve the sides of a right triangle with the angle measurements of 90, 52, and 38. And the length of the side between 52 and 90 degrees.

Answer 3

please draw a figure first

Answer 4

See, the side opposite to 38 Degrees angle is Perpendicular Side and Adjacent to it towards 90 Degrees is Base..

Like:

Answer 5

Getting??

Answer 6

I understand that, but I do not understand the process to finding out how to find the length of the base.

Answer 7

do you know about trigonometry?

Answer 8

That's what I am currently learning, and I'm struggling to grasp it.

Answer 9

Okay..

So now,

Remember: If you know the angle that is in case here is 38 Degrees and you know one side that is Perpendicular Side, then you can find the base by using:

\[\tan(\theta) = \frac{Perpendicular}{Base}\]

\(\theta\) = 38, Perpendicular = 128,000..

Can you find the Base here??

Answer 10

you might want to watch this video as well https://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/example--trig-to-solve-the-sides-and-angles-of-a-right-triangle

Answer 11

You need to find here \(tan(38^\circ)\) with using Calculator..

Answer 12

To find the Hypotenuse Side, you can go by:
\[\sin(38^\circ) = \frac{Perpendicular}{Hypotenuse}\]

Answer 13

38 times 128,000?

Answer 14

Or in simple case, you can use Pythagorean Theorem which says:
\[(Perpendicular)^2 + (Base)^2 = (Hypotenuse)^2\]

Answer 15

No..

Firstly find what is tan(38) using calculator..

Answer 16

okay. tan(38) is 0.31, correct?

Answer 17

Check it once again..

Answer 18

0.78?

Answer 19

is that right?

Answer 20

tan(38) is 0.31..