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Mathematics 15 Online
OpenStudy (anonymous):

how to do this help? will become fan. EXPLAIN.

OpenStudy (anonymous):

OpenStudy (anonymous):

remember that we have two nice rules for a triangle 1) sine rule -> when we have an angle and side opposite to it - > easiest 2) cosine rule -> when we do not have any angles but all sides -> a wee bit longer

OpenStudy (anonymous):

this this case, we have the angle B and the side opposite to it, we have the side "a" and need to find the opposite angle A so, we use sine rule \[{\sin A\over a}={\sin B\over b}\\ {\sin A\over23}={\sin(50^\circ)\over19} \]

OpenStudy (anonymous):

@electrokid I get 66.9?

OpenStudy (anonymous):

@electrokid but thats not in my answers?:o

OpenStudy (anonymous):

\[\sin A=23\times{0.766\over19}=0.927\\ A=\sin^{-1}(0.927)=? \]

OpenStudy (anonymous):

67.97

OpenStudy (anonymous):

\(68^\circ\) is not an answer?

OpenStudy (anonymous):

Alright I got it thank you. Could you help me with this one please?

OpenStudy (anonymous):

so, what rule can we use here?

OpenStudy (anonymous):

sine

OpenStudy (anonymous):

did you follow the rules I put up in the first post?

OpenStudy (anonymous):

Im so sorry I meant cosine!

OpenStudy (anonymous):

k. so set up the equation for cosine rule for angle R

OpenStudy (anonymous):

equation : 8^2 = 4^ + 7^2 - 2(4)(7) cos R?

OpenStudy (anonymous):

@electrokid

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Alright I got 89.02

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