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2/(n +5) - 3/(n +1)
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You want to start by getting a common denominator! Just like how you would with numerical fractions, you do with these algebraic ones. \[\frac{ 2 }{ (n-5) }-\frac{ 3 }{ (n+1) }=\frac{ 2(n+1) }{ (n-5)(n+1) }-\frac{ 3(n-5) }{ (n-5)n+1) }\] Try finishing it off by distributing the numerators, subtracting the fractions, then simplifying and seeing if anything cancels!
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