Can someone please help me with this I have no idea how to do this Solve: 3(x + 4) x - 2
distribute the 3, then combine like terms
what do you mean?
does the question look like this: 3(x+4)(x-2) ?
or like: 3(x+4) + x -2 ?
it says 3(x+4)(ge) x-2
(ge) ???
3(x+4)\[(\ge) \] x-2
it wont let me type it all together
3(x+4) >= x -2 3x + 12 >= x -2 That's what I mean by distribute. Can you solve from here?
do i add 2 to both sides?
you can. i like to get the variables on one side and the constants on the other. that way we can solve for x by itself.
okay once i get 14 what do i do from there?
I would have solved it like this: 3x + 12 >= x -2 subtract x from both sides 2x + 12 >= -2 subtract 12 from both sides 2x >= -14 divide both sides by 2 x >= -7
so did i do it backwards?
it doesnt matter which way you do it, as long as you get x >= -7. that can also be written as -7 <= x
oh okay im not understanding what did you do to the 3? but thank you soooo much!
3x + 12 >= x - 2 Here I subtracted x from both sides If you do that you end up with: 2x + 12 >= -2 3x - x = 2x
do you see?
so what do you do with the -2?
i left it where it was, but i subtracted -12 from both sides so i got: 2x >= -14 -12 - 2 = -14
ohhh okay i think i get it! thanks so much
cool, anytime!
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