Question

Find the equation of a line with the give properties:

Through (6, 2) and perpendicular to the line with x-intercept 2 and y-intercept -3

Answer 1

y = mx +c

using 2 points the line, (x1, y1) and (x2, y2), where x2 > x1:

\[m = \frac{y_2 - y_1}{x_2-x_1} \]

c is value of y when x = 0.

notice that the questions gives you 3 points, (6,2), (2,0) and (0,3).

try solving using the method outlined above.

Answer 2

@tridian I don't think so. the required line perpendicular to that line, it means dot product of 2 directions of two line is =0

Answer 3

I think , we have to find out the equation of the line with x-intercept =2 and y-intercept =-3 to have it direction d_1

Answer 4

then, use property of perpendicular vector to find out the direction d_2 of the required line
from that direction + the given point, write down the equation of the line.
slope line is just for the given line only.

Answer 5

thank you!

Answer 6

np

Answer 7

@Hoa oops, misread the question. thanks for spotting.