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Mathematics 19 Online
OpenStudy (lukecrayonz):

The position of an object at time t is given by s(t) 3-4t. Find the instantaneous velocity at t=8 by finding the derivative.

OpenStudy (lukecrayonz):

@Mertsj

OpenStudy (lukecrayonz):

@Brandon77

OpenStudy (anonymous):

Did you see my comments on the other question about taking the derivative

OpenStudy (lukecrayonz):

So it's -4..?

OpenStudy (anonymous):

the derivative of a constant number (like 3) is 0 the derviative of a number times a t (like -4t) is just the number (-4)

OpenStudy (anonymous):

and so yes thats right

OpenStudy (lukecrayonz):

So when t=8..?

OpenStudy (anonymous):

since the position function is a straight line, then the velocity will be constant for all time

OpenStudy (anonymous):

so it will always be -4

OpenStudy (lukecrayonz):

So what exactly is a derivative in definition? I'm sure you can explain it better than some websites :P

OpenStudy (anonymous):

okay. for a line you can calculate the slope by using two different points (rise over run) but a dervative is like moving those two points so close together its like taking the slope of a single point.

OpenStudy (anonymous):

derivative*

OpenStudy (anonymous):

since the slope is being taken at a single point, there is no ∆ x like a two point equation (rise/run = ∆y/∆x) so its the slope of a point at a single instant in time

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