Ask your own question, for FREE!
Chemistry 12 Online
OpenStudy (anonymous):

How many milliliters of a stock solution of 5.00 M KNO3 would you need to prepare 250 mL of 0.250 M KNO3?

OpenStudy (anonymous):

so the equation you need here is M1v1=M2v2

OpenStudy (anonymous):

yes thats right @peter14

OpenStudy (anonymous):

so then what would i do next?

OpenStudy (anonymous):

you know the initial molarity, the final molarity, and the final volume

OpenStudy (anonymous):

plug it into the equation

OpenStudy (anonymous):

do you get the answer @selenamalter ?

OpenStudy (anonymous):

no, im a little confused still

OpenStudy (mertsj):

Substitute. Do you know what the letters in the formula stand for?

OpenStudy (anonymous):

it same with peter's formula M1 v1 = M2 V2 5 v1 = 0.25 x 250 get it?

OpenStudy (mertsj):

|dw:1366684902405:dw|

OpenStudy (anonymous):

okay, let me see here

OpenStudy (anonymous):

1.25?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!