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Find the amount of work done in emptying a cylindrical tank completely filled with kerosene. Assume that the radius of the cylindrical tank is 3 m, height is 6 m, and the density of kerosene is 817.15 kg/m3.
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You can assume whole centre of gravity of the kerosene at the cylinder's center of gravity as whole body(kerosene) moves with same veocity as this is translational motion then using work-energy theorem ( \[\Delta u = \Delta k\]on centre of gravity of kerosene assuming no change in kinetic energy (i.e. rest to rest,using conservation of energy)
u can do it in other way that involves work-energy theorem and some common techniques of integeration. anyway answer is 4075611.209 Joule if you take g=9.8m/s^2
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