Question

|3x| + 36 > 12 SOLVE INEQUALITY

Answer 1

Our aim is to have x (or whatever the variable is) on its own on the left of the inequality sign:

3x +36 > 12

Answer 2

3x+36-36 > 12-36

sol- 3x>-24

Answer 3

-8 @Rohangrr

Answer 4

nope the answer is 3x>-24

Answer 5

Subtract both sides by 36.
\[|3x| > -24\]
\(|3x|\) is always \(\ge 0\) so \(x \in \mathbb{R}\)

Answer 6

THESE ARE THE ANSWERS A.-8 > x > 8 B.all real numbers are solutions C.x < -8 or x > 8
D.-8 < x < 8

Answer 7

@Rohangrr

Answer 8

Read my reply above here. It's B.

Answer 9

OK

Answer 10

You seem like you don't understand, do I need to clarify something?

Answer 11

NO I SAW YOUR REPLY

Answer 12

Ok, so is it clear?

Answer 13

@reaven I had given the same answer.

Answer 14

YES

Answer 15

@Rohangrr Didn't you notice the absolute value?

Answer 16

YES

Answer 17

Well, Rohangrr forgot to include the absolute value so his answer is wrong. just saying.

Answer 18

SO MY ANSWER ISNT b @geerky42

Answer 19

It is B. Rohangrr's answer is different.

Answer 20

OK

Answer 21

Remember, an absolute value is always positive. So, despite our what our algebra tells us, the absolute value has to be at least zero. After we have that in mind, we get\[\left| 3x \right|>0\]Which indicates x can be any number except zero. The solution set would look like\[x \in \mathbb{R}-\left\{ 0 \right\}=(-\infty , 0) \cup (0, \infty) = \left\{ x \in \mathbb{R}|x \ne 0 \right\}\]

Answer 22

Correction to above: an absolute value is always nonnegative.

Answer 23

@AnimalAin but when x = 0, 36 > 12, which is true so 0 is also solution.

Answer 24

Actually, I suppose my deletion of zero isn't really needed in this case.

Answer 25

Solution:\[x \in \mathbb{R}\]

Answer 26

Yup.