a golf ball is packed into a cubical box so that it just fits. what percentage of the box is unfilled?
volume of box - volume of ball
divide by volume of box
That is what I did. Isn't the 2x radius the same as length, width, height of the cubic box?
foe a cube length=breadth=height=l volume=l^3 volume of ball=4/3*pi*r^3
My answer is 476.4%
Is that how we do it?
(l^3-4/3*pi*r^3)/l^3
ans will be less than 100%
You'll get a different answer (0.869)
numerator will be less then denominator let ans is 0.99999 for % calculation 0.99999*100=99.999 so it can not go above 100 give me the value i will solve fr u
They haven't given a value but one can conclude that if the radius is 5 then the height, length and width are all equal to 10 as the golf ball perfectly fits the cubic box
You would need to draw it
|dw:1366720950700:dw| to find the percentage of the box that is unfilled you can just find the percentage of the box that is filled and subtract that from 100%
to find this, you can assume the radius of the sphere to be 1, which makes the side length of the box 2, your reasoning above is correct.
area of a cube = side^3 = 8 area of a sphere = 4/3 pi*r^3 = 4/3 pi
so the percent filled is \[\frac {\frac{ 4 }{ 3 }\times \pi}{8}\]
and from there you can find the percent empty @Chad123 you see how this works?
@Peter14 we have to calculate empty space ratio so (8-4*pi/3)/8
Thanks guys
yes, @gorv I specified earlier that you subtract the percent filled space from 100
So we don't have to convert the answer into a %?
@Peter14 actually i didn't see that sorry for that
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