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integrate f(q)= (q -4)² - 12
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why not expand the brackets first then differentiate?
expand the brackets first then integrate
(a-b)^2 = a^2-2ab + b^2
Nope no need to expand. \[\int\limits [(q-4)^2-12] dq\] \[\frac{1}{3}(q-4)^3-12q+C\]
Anti-differentiate.
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Anti-differentiating is one of the fastest ways to integration unless there comes a time when anti-differentiation starts to not work, then you go to other methods (eg. Using partial fractions" to integrate).
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