Given: Area of the triangle is 40 and its sides are 40,35,55 cm. find the length of the longest altitude.
1/2*base*height=40
calculate height
base=?
\[A=\frac{1}{2}ab\sin\theta\]
\[\cos\theta=\frac{a^2+b^2-c^2}{2(a)(b)}\]
put all the length in place of base the maximum value of height willbe your answer
@gorv A=1/2 bh only works for right angled triangles. >.>
@Azteck we have to calculate height and it works for mst of the triangls okkk if i m wrong tell altitude by ur formula??
But it also applies if you know which side is the base.
@Azteck A=1/2 bh works for any type of triangle......only if you are given the required lengths......
thats wat i m saying the side which will give max altitude will be considered as base
35 will give max height so take it as base
how 35 cmes base
put all the sides in formula told base =35 will give max altitude that is height so side=35 will be consideredas the base
k
i got it
@gorv thanks bro
take same approch
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