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Mathematics 6 Online
OpenStudy (anonymous):

integrate lnxdx

OpenStudy (anonymous):

TIP: You can do this one using integration by parts...

OpenStudy (anonymous):

please help me out

OpenStudy (gorv):

ln(x) dx = x ln(x) - int (1/x)x dx = x ln(x) - int 1 dx x ln(x) - x

OpenStudy (anonymous):

Aww you beat me, but I'll type anyway

OpenStudy (gorv):

or ln(x) dx set u = ln(x), dv = dx then we find du = (1/x) dx, v = x substitute ln(x) dx = u dv and use integration by parts = uv - v du substitute u=ln(x), v=x, and du=(1/x)dx = ln(x) x - x (1/x) dx = ln(x) x - dx = ln(x) x - x + C = x ln(x) - x + C.

OpenStudy (anonymous):

Nevermind hahah

OpenStudy (gorv):

@taljaards hey buddy we r not here to beat each other it is pssible that he didn't get mine bt can get urs ...its not ur defeat n mine victory

OpenStudy (anonymous):

Hahahah I know :) Nope, my method was exactly the same as yours. Thanks for the quick reply, I'm sure the asker appreciates - I always do when asking a Q :)

OpenStudy (anonymous):

i highly appreciate your help guys. thanks a lot

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