dy/dx = (y+8x)/(x+2y) I know the way to the solution is long therefore if you can please tell me what method are you using for the solution and what is the final answer? tnx :)
btw I used F(y/x)=v(x)
take x common from Nmr. n Dnr. and put y=vx and then replace dy/dx by v+x(dv/dx) and solve accordingly
I've done that, that's where things got ugly
I replaced the dv/dx with dx/dv and isolated the dx/dv on one side minus all the X's and got a Homogeneous equation for x(v)
btw sry for my lingo, my main language is not English
I got a solution for x(v) \[x(v)=ce ^{(4-v^2)^(3/8)}\]
u must have got this\[x(dv/dx)=2(4-v^2)/1+2v\]
the main problem is that I'm not sure about my final answer
yep
that's where I changed the equation from v(x) based to x(v) based. is that what I should have done or is there another way? because when I'm doing this I'm getting a Homogeneous equation which is easy to solve
after solving u'll get 2+v/(2-v)(4-v^2)^2=x^8c
ok tnx and if I want to get the : y(x) I need to isolate the v annd put it in the first equation - y(x)=x*v(x) ?
oh yes to get final answer put v=y/x. Are u in high school?
lol no
I'm taking a course in Linear differential equation this is from the homework of the second week
solve this one dy/dx= x+3y+2/3x+9y+6
sorry this one dy/dx= x+3y+2/3x+9y+5
dy/dx=1/3 y(x)=1/3*x
ohh that will take me a few minutes
-(3x+9y+5)dy+(x+3y+2)dx=0 from here we need to make it into an exact equation
hey no need for that it can be solve easily
sry this is an exact equation
any way Shiv tnx for the help I need to go to another class :)
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