Question

Two identical, parallel, thin metal plates are connected to the terminals of a DC power supply.

Answer 1

a) It can be shown that the electric field produced by a large, thin, metal plate with uniform surface charge density σ, at relatively small distances from the plate, can be expressed as , where is the surface normal unit vector. Derive an expression for the electric field between the plates mentioned above in terms of their charge density σ if the distance d between the plates is much smaller than their dimensions;
b) Using integration, derive an expression for the potential difference between

Answer 2

\[E=\frac{ \sigma }{ 2\epsilon _{0} }\eta \]

Answer 3

... can be expressed as (above formula), where n ....

Answer 4

Don't know physics. Sorry.

Answer 5

@UnkleRhaukus

Answer 6

what does eta represent here?

Answer 7

something like the dielectric constant of the material between the plates or something else?

Answer 8

im not sure what eta '\(\eta\) ' means here

Answer 9

uniform surface charge density σ
n is the surface normal unit vector

Answer 10

\[\hat{\mathbf n}\]

Answer 11

yes, i couldn't find it

Answer 12

ah ok, so you have to show

\[\large\vec E=\frac{ \sigma }{ 2\epsilon _{0} }\hat{\mathbf n}\]

```
\[\large\vec E=\frac{ \sigma }{ 2\epsilon _{0} }\hat{\mathbf n}\]
``

Answer 13

yes, thx