Question

5(1-x)-2=3x-4

Answer 1

Could you show us what you've done so far regarding your question please?

Answer 2

i dont know what to do first.... i think 5(4x-x)-2 ??

Answer 3

Okay, well let's start off by expanding/distributing the LHS [Left Hand Side]. Could you do that for me and tell me what you get?

Answer 4

?

Answer 5

Okay the left hand side says:
\[5(1-x)-2\]
Am I right?

Answer 6

yes

Answer 7

yes

Answer 8

And we're looking to distribute/expand 5(1-x). In other words, we want to eliminate the brackets or paranthesis, etc. If you get rid of the brackets, you end up with this [sorry for the irony but I placed more brackets to let you get a clearer understanding):
\[5(1-x)=(5\times 1) + (5\times x)\]
can you do the

Answer 9

And it's meant to be a minus sign in the middle.

Answer 10

SOrry about that typo
\[5(1-x)=(5\times 1)-(5\times x)\]

Answer 11

So can you complete the right hand side for me? So what's 5 times 1 equal to? And what's 5 times x equal to?

Answer 12

so would i expand the right side as well:

x+x+x-4

Answer 13

So could you complete the Right Hand Side where it says in one of the paranthesis, "what 5 times 1 is equal to?"?

Answer 14

i see

Answer 15

As well as the other bracket/paranthesis saying what "5 times x is equal to". Give me your full answer.

Answer 16

5(4-x)=(5x x)..

Answer 17

5 time 1 equals 5 5 times x equals 5

Answer 18

wow its been a very long time sorry

Answer 19

\[\large 5\times x=5?\]

Answer 20

? i am not understanding

Answer 21

\[\large 5\times x=5x\]
Do you understand this part?

Answer 22

yes

Answer 23

So
\[\large (5\times 1)-(5\times x)=5-5x\]

Answer 24

YES

Answer 25

Now we've done part of the LHS:
\[\huge 5(1-x)-2=5-5x-2\]

Answer 26

Could you simplify the RHS for me please?

Answer 27

@Jrcroley123 you there?

Answer 28

hmmm

Answer 29

would i add another variable

Answer 30

like y?

Answer 31

No, I jsut want you to simplify that. So you're just collecting like thems. For example:
\[x+2x+5-2=3x+3\]

Answer 32

just*

Answer 33

like terms*

Answer 34

6(x)+3

Answer 35

Where did you get that from?
\[\large 5(1−x)−2=5−5x−2\]
\[\large 5-5x-2=?\]

Answer 36

So basically you're ignoring the -5x, and you're calculating what 5-2 is equal to.

Answer 37

because there isn't anymore "x-terms" to gather up.

Answer 38

You're gathering up the constants, which is 5-2.

Answer 39

what's 5-2 equal to?

Answer 40

3

Answer 41

Yeah so
\[\large 5−5x−2=3-5x\]

Answer 42

That's the LHS done. Now we have this equation:
\[\huge 3-5x=x-4\]

Answer 43

Let's move the -5x to the RHS. That means the -5x becomes 5x once it's moved to the RHS. Always change the sign of a term when you move it to the other side of the equal sign.

Answer 44

So we have
\[\huge 3=x-4+5x\]

Answer 45

Let's move the -4 to the other. what would the equation look like now if you move the -4 to the LHS.

Answer 46

to the otherside*

Answer 47

3+4=x+5x

Answer 48

7=x+5x

Answer 49

7/4

Answer 50

7/4?
\[x+5x=4x??!?!?!?\]

Answer 51

ha im sorry i have to get to class...ill ask my tutor thanks for your help I do understand a little more

Answer 52

Umm, you're almost finished.
\[\large x+5x=6x\]
So
\[\large 6x=7\]
\[\large x=\frac{7}{6}\]

Answer 53

You were on the right track but you somhow thought 5x+x was 4x, instead of 6x.

Answer 54

somehow*