Question

2y/y(3y-1)+5/3y-1

Answer 1

@mistymash
is this
\[\frac{ 2y }{y( 3y-1) } +\frac{ 5 }{ 3y-1 }\] ????

Answer 2

yes

Answer 3

look at the first term
\[\frac{ 3y }{ y(3y-1) }\]
can u write above in any other form or cancel any term?

Answer 4

3y cancels out

Answer 5

so i would be left with y-1?

Answer 6

no y would cancel out
as it is y * (3y-1) in the denominator
is this ok?

Answer 7

i am way confused

Answer 8

ok dont do in this way
lets do in the more simpler way
in general,
\[\frac{ 1 }{ a } + \frac{ 1 }{ b } = \frac{ b+a }{ ab }\]

Answer 9

7/3y-1?

Answer 10

we have been given
\[\frac{ 2y }{ y(3y-1) } + \frac{ 5 }{ 3y-1 } = \frac{ 2y + 5y }{ y(3y-1) }\]

Answer 11

yeah it will be \[\frac{ 7 }{ 3y-1 }\]

Answer 12

thank you for all your help you are awsome!!!

Answer 13

:-)