Question

Help with Simplifying Radicals
1. *square root* 49a^8
2. 2 *square root* 10 *times* 3 *square root* 12
3. *square root * 14q *times* 2 *square root* 4q
4. 4/ *square root* 11
i really hope you understand me please help me ❤❤❤❤❤❤

Answer 1

1. \[\sqrt{49 a^8}=\sqrt{7^2(a^4)^2}=7a^4\]
2.\[\sqrt{10}\sqrt[3]{12}=10^{1/2}12^{1/3}=10^{3/6}12^{2/6}=\sqrt[6]{10^312^2}\]
3.\[\sqrt{14q}\sqrt{4q}=\sqrt{64q^2}=8q\]
4.\[4\sqrt{11}=\sqrt{11\cdot4^2}\]

May be I missunderstand some of your questions. Tell me if that is the case.

Answer 2

well actually only one of them is right lol let me see if i can do it with the butttons on here

Answer 3

thats number 3. 2\[2 \sqrt{10}\times 2 \sqrt{4q}\]

Answer 4

I mean number 3

Answer 5

3) \[2\sqrt{10}2\sqrt{4q}=4\sqrt{40q}=4\sqrt{2^2\cdot10}=8\sqrt{10}\]
I suppose it is right now. Check it :).

Answer 6

4. \[\sqrt{14q}\times 2 \sqrt{4q}\]

Answer 7

and for number 3 that answer is not in my options .-.

Answer 8

52
John_ES 0
Umm, the factor 2 is the exponent of the radix or a constant factor? If it is the exponent, then,
\[\sqrt{10}\sqrt{4q}=\sqrt{40q}=2\sqrt{10q}\]

Answer 9

im so sorry i suck at this :c the 2 for what number ? lol im sorry

Answer 10

I say the number 2 in front of the square root
\[2\sqrt{}\]
As you write is a number that multiplies the square root. But in this other form
\[\sqrt[2]{}\]
is the exponent.
Which of these forms are in your exercise?

Answer 11

May be it should be better if you can capture an image of the exercise.

Answer 12

oh no thats a regular number just like the top one

Answer 13

i don't have a screenshot on my laptop

Answer 14

Sorry for the absence. For the fourth question,

\[\sqrt{14q}\times2\times\sqrt{4q}=4q\sqrt{14}\].
(You can take a screenshot with the button Imp. Pant, just in the upper-right part of the keyboard. Then, you can use paint to paste the content of the notepad and save it as png)