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How do I find the ionic form of this unbalanced equation...? MnO2+HNO2 = MN(NO3)2+H2O
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To write a complete ionic equation, first start with balancing the molecular equation. Next you break all soluble electrolytes (compouds with (aq)) into their ions, compounds with (s),(l) and (g) are unchanged.
If you would change the unbalanced equation in the ionic form you just skip step 1 So it would be:\[Mn ^{2+}+O_2^{-}+H^{+}+NO_2^- \rightarrow Mn^{2+}+NO_3^-+H_2O\]
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