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Evaluate log2 1/8.
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\[\log_{2}\frac{1}{8}= x \]
What is the base?
2?
What is the exponent?
x
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So we have: \[2^x\]
What does that equal?
2^x=1/8?
Now replace 8 with a power of 2
8 = 2^?
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@Tomo Let the asker answer the questions.
ok, yes, i was trying to help the user understand the following concept \[\ln_x{x^y} = y*\ln_x{x} = y*1 = 1\]
2^x=2^3?
\[2^x=\frac{1}{2^3}\]
Now move the 2^3 to the numerator
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2^x=-2^3?
\[2^x=2^{-3}\]
The bases are the same, the expressions are equal so the exponents must be equal.
So for log5 1/125, x=-3?
yes. Good for you!!
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Thank you!
yw
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