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Use an inverse property to evaluate 6^(log 6 19).
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First, I would like for you to understand this. Then after you understand...it will become automatic.
Think about the exponent only: \[\log_{6}19 \]
A log is an exponent so that expression is talking about an exponent
And this is the exponent it is referencing: it is an exponent that should be placed on the base 6. Do you understand that?
So would I first evaluate log6 19?
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Do you understand what I wrote so far?
I believe so.
And if that exponent is placed on the base 6, the result will be 19
So notice...in this problem, that exponent HAS BEEN PLACED on the base 6. So what is the result?
|dw:1366755531052:dw|
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