Question

please help me simplify...

Answer 1

\[\frac{ 1x }{ x^2-4x-12 } - \frac{ 3x }{ 4x+8 }\]

Answer 2

\[\frac{ x }{ x^2 -4x-12}-\frac{ 3x }{ 4x+8 }\]What you can do is factor the denominator:\[\frac{ x }{ (x-6)(x+2) }-\frac{ 3x }{ 4(x+2) }\]You can see that (x+2) is repeated in both fractions, what you need to do is to NOT copy it twice. Count it as one of the factors when you combine this two fractions. In getting the common denominator, multiply everything. \[\frac{ ? }{ (x-6)(x+2)(4) }\]In this one, divide this denominator to the original one. I'll be back got to go out for a bit. Hope that gives you the idea on how to start. :)

Answer 3

si you are left with 3x on the top?

Answer 4

so not si

Answer 5

?

Answer 6

For the first term you would get: