Question

Find the dimensions of the rectangle of largest area that has its base on the x-axis and its other two vertices above the x-axis and lying on the parabola y=2−x2.
Width =
Height =

Answer 1

the base of your rectangle will be \(2x\) and the height will be \(2-x^2\) so the area will be \[A(x)=2x(2-x^2)\]
maximize that one

Answer 2

so i took the derivative of that and then set that equal to zero and solved for x which equals .8164965

Answer 3

Where do i go from here?