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Mathematics 18 Online
OpenStudy (anonymous):

How do I find the solution y(x) for 0 ≤ x ≤ π for this boundary value problem? y''=y/25=Σ1/n sin(nx) y(0)=y(π)=0 I know I'm supposed to use y(x)=ΣBn sin(nx), and the answer is supposed to be Bn=1/(n(1/25)-n^2), but I have no idea how to get there. Thanks for the help.

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