prove by induction...
1/0!+1/1!+1/2!+...+1/n!

Question

prove by induction...
1/0!+1/1!+1/2!+...+1/n!<3-(2/[n+1]!)

anonymous · Answer

Could you show us what you've done so far please.

anonymous · Answer

base case: n=2 ... 1/2! <3-2/3!

ind: 1/[(k+1)+1]!<3-2/(k+1)!+1/(k+1)!


not coming out equal...

anonymous · Answer

Inequalities can be a bugger of a question when it comes to mathematical induction. Sometimes, if it doesn't work, you try and give a "forced" statement, for example: 8<9 which is true.

anonymous · Answer

Okay for n=k+1, what would the LHS become? COuld you write that out for me please?

anonymous · Answer

I figured it out thanks though...

anonymous · Answer

Oh, okay, it seems you did some sort of mistake. Happens to everybody, don't worry. WEll done for being persistent witht he question. That's a good trait for being a good mathematician. ;)

anonymous · Answer

with the*