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Mathematics 9 Online
OpenStudy (anonymous):

prove by induction... 1/0!+1/1!+1/2!+...+1/n!<3-(2/[n+1]!)

OpenStudy (anonymous):

Could you show us what you've done so far please.

OpenStudy (anonymous):

base case: n=2 ... 1/2! <3-2/3! ind: 1/[(k+1)+1]!<3-2/(k+1)!+1/(k+1)! not coming out equal...

OpenStudy (anonymous):

Inequalities can be a bugger of a question when it comes to mathematical induction. Sometimes, if it doesn't work, you try and give a "forced" statement, for example: 8<9 which is true.

OpenStudy (anonymous):

Okay for n=k+1, what would the LHS become? COuld you write that out for me please?

OpenStudy (anonymous):

I figured it out thanks though...

OpenStudy (anonymous):

Oh, okay, it seems you did some sort of mistake. Happens to everybody, don't worry. WEll done for being persistent witht he question. That's a good trait for being a good mathematician. ;)

OpenStudy (anonymous):

with the*

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