Determine if each function is continuous. If the function is not continuous, find the x-axis location of and classify each discontinuity.
\[f(x)=\frac{ x+1 }{ x^2-x-2 }\]
P.D.: 2,-1
This is where factoring the denominator might come in handy.
the (x+1) cancel out right?
Okay, you seem to have gotten it... now to classify... If a certain point of discontinuity makes the denominator and ONLY the denominator zero, then it is an infinite discontinuity. On the other hand, if a certain point of discontinuity makes BOTH the numerator and denominator zero, then it is a removable discontinuity (or a hole).
I think there is a hole at x=1?
x = 1 is not even a point of discontinuity... check the P.D's you gave me :)
the hole is at x=-1? but then the equation would be 0/(x-2)
hole is at x = -1 because at x = -1, both the numerator and denominator are zero :)
So it's a removable discontinuity.
Yup. And the other one, x = 2 ?
? umm they're both removable?
or is that the x-axis location?
No... I said... a P.D. would be removable if it makes BOTH the numerator and denominator zero ... so check
x=2 only makes the denominator 0
So... is it a removable discontinuity?
No
Then what is it...?
So it's an infinite discontinuity right?
Yup.
when they say x-axis location, would that be x=2?
Yes.
alright once again thank you, that was my last question, i can finish the rest xD
Awesome :)
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