Question

plse help me to solve this

Answer 1

Say we have a triangle...

Answer 2

It will have three altitudes... thisthisand this

Answer 3

Catch me so far?

Answer 4

yes

Answer 5

These three altitudes are different, no?

Answer 6

However, for instance, in this case...
the length 61 serves as a base for this triangle corresponding to the height (altitude) \(h_1\)

So the area of this triangle can be expressed \[\huge \frac{bh}2=\frac{61h_1}{2}\]

Answer 7

Agree, @msingh ?

Answer 8

how 61 serve as a base
i have only doubt about base

Answer 9

A base is a side of the triangle that is perpendicular to its height... and since the side measuring 61 is perpendicular to the height (altitude) \(h_1\) then it is the base.
So the area of the triangle is
\[\huge \frac{61h_1}{2}=939.148\]
Now you can solve for \(h_1\)

Answer 10

okay

Answer 11

Solve for \(h_1\) what do you get?

Answer 12

h1=30.79

Answer 13

That's strange, I get 30.54...

Answer 14

whoops, a typo... Okay, you are correct @msingh
Now...

Answer 15

its okay bro

Answer 16

Can you get the value of \(h_2\) in a similar fashion?

Answer 17

okay one by one i have to take 6 base, ,,35 base and 54 base and find out the height
and out of three heights , the greater height will be an answer

Answer 18

Yes.
Since you seem to have gotten it, please post your answer when you're done :)

Answer 19

yeah sure,

Answer 20

when 35cm is taken
then height = 53.66
and when 54cm, then height =34.78

Answer 21

Bingo. So your final answer would be...?

Answer 22

35cm

Answer 23

^not an altitude.

Answer 24

srry 53.6

Answer 25

Nicely done :)

Answer 26

@terenzreignz thanks bro

Answer 27

Call me Terence, and we'll get along splendidly :)

Answer 28

okay