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Mathematics 12 Online
OpenStudy (anonymous):

f(x)=−3+8x−x^3 (A) Use interval notation to indicate where f(x) is increasing. Note: Use 'INF' for , '-INF' for −, and use 'U' for the union symbol. Increasing: (B) Use interval notation to indicate where f(x) is decreasing. Decreasing: (C) List the x values of all local maxima of f. If there are no local maxima, enter 'NONE'. x values of local maximums = (D) List the x values of all local minima of f. If there are no local minima, enter 'NONE'. x values of local minimums =

OpenStudy (anonymous):

has u find the derivative?

OpenStudy (anonymous):

yeah i did but i dont know what to do from there

OpenStudy (anonymous):

and the critical points?

OpenStudy (anonymous):

yeah im not sure if they are right but i got sqrt 8/3 and -sqrt8/3

OpenStudy (anonymous):

mmmm let me check

OpenStudy (anonymous):

give me 2 min

OpenStudy (anonymous):

sqrt(8/9) ?

OpenStudy (anonymous):

yeah and i took the sqrt of the bottom

OpenStudy (anonymous):

mmm i understand yes the critical points r right

OpenStudy (anonymous):

so from there what do i do

OpenStudy (anonymous):

well u have some intervals now

OpenStudy (anonymous):

do u know whic intervals?

OpenStudy (anonymous):

no im not really sure

OpenStudy (anonymous):

ok u have the critical points that points give u some intervals that is (-INF, -sqrt(8/9) (-sqrt(8/9), sqrt(8/9)) (sqrt(8/9) , INF)

OpenStudy (anonymous):

3 intervals given by the critical points

OpenStudy (anonymous):

im still a bit confuse on how im suppose to know which is a max and which is a min

OpenStudy (anonymous):

well the critical points must be the max and the min

OpenStudy (anonymous):

do u got that?

OpenStudy (anonymous):

yeah i think so lol

OpenStudy (anonymous):

ok but u must determine if a critical point is a max or a min

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