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Physics 7 Online
OpenStudy (anonymous):

how do you calculate root-mean-square (r.m.s) speed??

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Root-mean-square_speed this is if u meant gases

OpenStudy (anonymous):

\[Vrms = \sqrt{3RT/M}\]

OpenStudy (anonymous):

actually, in my question, i am supposed to find the root mean square speed of helium atoms.....i was given the formula \[pV=\frac{ 1 }{ 3 }Nm <c ^{2}> \]

OpenStudy (anonymous):

i was given the pressure(p) = 6.1 x 10^5 Pa Volume (V)= 2.1 x 10^4 cm^3 number of atoms (N)= 3.26 x 10^24

OpenStudy (anonymous):

but i do not know why i am getting the answer wrong....

OpenStudy (anonymous):

\[<c ^{2}>= mean -squared-speed\]

OpenStudy (anonymous):

See: \[pV = \frac{ 1 }{ 3 }Nm<c^{2}>\] \[\sqrt{\frac{ 3pV }{ Nm }} = Vrms\] We know that\[PV=NRT\] So: \[\frac{ PV }{ N } = RT\] Then: \[\sqrt{\frac{ 3RT }{ M }} = Vrms\] So now u can use the values of p V and N as given to u in the question and follow the reverse of this derivation.

OpenStudy (anonymous):

is the m the same as M

OpenStudy (anonymous):

??

OpenStudy (anonymous):

It is same if m means mass of 1 mole of the gas. So??????

OpenStudy (anonymous):

so does that mean it would be 4 for the helium atom???

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

oh......i found my mistake...... thanks for the explanation!!

OpenStudy (anonymous):

thnx for the medal

OpenStudy (anonymous):

yw:)

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