Solve for x :
[x]^3 - 2[x] + 1 = 0
([.] is the greatest integer function)
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OpenStudy (anonymous):
let [x]=t
so t comes out to be 1 and some other 2 roots
[x]=1 so 1<x<2
:)
OpenStudy (anonymous):
@Aperogalics - x can also take '1' :)
OpenStudy (anonymous):
ya i just type it but think it is not typed ;)
OpenStudy (anonymous):
its cubic equation bro, not quadratic
OpenStudy (anonymous):
Yes by trial [x]= 1 is solution.
Diving the poly by [x]-1(factor), we get : \[[x]^{2} + [x] - 1\]
which doesnt have any integral solution
Hence the solution of the poly is : 1\[\le x < 2\]
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OpenStudy (anonymous):
aww.. thanx <3
OpenStudy (anonymous):
Welcome :)
terenzreignz (terenzreignz):
Where are you getting these questions @vikrantg4 ?!
OpenStudy (anonymous):
My coaching institute's study material assignments.
OpenStudy (anonymous):
Which coaching? U r in 11 or 12?
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OpenStudy (anonymous):
12.. fiitjee ;)
OpenStudy (anonymous):
Fiitjee zindabad...I'm a fiitjee student too :D cheers!
OpenStudy (anonymous):
wahh :D lol
OpenStudy (anonymous):
u in 12th too ?
OpenStudy (anonymous):
No last year passout..dropping...exam season on!
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