Question

Find range:

Answer 1

y=[sinx+[cosx+[tanx+[secx]]]

Answer 2

The presence of a tangent hints the range being all real numbers... just a hunch :)

Answer 3

That's just an illusion,nowhere near the answer.

Answer 4

Go figure. :)

Answer 5

?

Answer 6

Just to be clear, this is a sum, right?
\[\large y = \sin(x) + \cos(x) + \tan(x) + \sec(x)\]
or am I missing something?

Answer 7

GREATEST INTEGER FUNCTION!

Answer 8

ya i ws thinking that only

Answer 9

OH... well, that changes things :D

Answer 10

GINT

Answer 11

Then all integers?

Answer 12

hahahaha

Answer 13

Just intuitively, the floor of sin and cos is almost negligible, and tangent can be as big, or as highly negative, as needed...

Answer 14

Answer is VERY VERY non intuitive :/

Answer 15

Is it all integers except 0??????

Answer 16

no

Answer 17

Well then, I'm lost :)

Answer 18

Do u know the correct answer???

Answer 19

yes

Answer 20

@hartnn

Answer 21

Start from the first box. Sec x has a range (\[(-\infty, -1] \cup [1, +\infty)\]
Then compute the box of it. Then add it to the absolute range of tan. Then compute this sum's box. Proceed like this. Tiresome job :|

Answer 22

If u proceed like this u get the answer as i hv mentioned above: all integers except 0

Answer 23

^^

Answer 24

What is the given ans?

Answer 25

{1}

Answer 26

Is there any justification for that range? Because firstly, it doesn't appear to make sense given the function, and also... http://www.wolframalpha.com/input/?i=y%3DFloor%5Bsinx%2BFloor%5Bcosx%2BFloor%5Btanx%2BFloor%5Bsecx%5D%5D%5D+

Answer 27

I agree with @Saikat26 and @lordcyborg

If you start from the inside and go out. you get a range of... all integers except zero.