LAW OF COSINES: FIND THE MISSING ANGLES FOR THIS TRIANGLE:

Question

anonymous · Answer

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ryan123345 · Answer

$$c^2=a^2+b^2-2ab \cos (c)$$

anonymous · Answer

So it would be..... $$6^{2}=17^{2}+12^{2}-2\times17\times12\cos C$$

parthkohli · Answer

Correct.

ryan123345 · Answer

good job

anonymous · Answer

angle  of bac is 139.19

anonymous · Answer

But that would only help you find angle C correct? Then you can use law of sines for the rest?

anonymous · Answer

I'm stuck on this part:
-397=-408 cos C

anonymous · Answer

Would you divide or how would you do it?

ryan123345 · Answer

cos(c)     cos(b)     cos(a)

anonymous · Answer

If a 20-sided fair die with sides distinctly numbered 1 through 20 is rolled, the probability that the answer is a perfect square can be expressed as ab where a and b are coprime positive integers. What is the value of a+b?

anonymous · Answer

plz help me

ryan123345 · Answer

$$a^2=b^2+c^2-2ab \cos(A)$$$$b^2=a^2+c^2-2ab \cos(B)$$$$c^2=a^2+b^2-2ab \cos(C)$$

ryan123345 · Answer

you use those formulas depending on what you are trying to find.

anonymous · Answer

Ok, but I got .9730392157 for the angle measurement...... Doesn't make since