log7 1/343
@BooBoo9512 Can you find the answer for this? \[7^x=343\] What power 7 has to be raised to get 343?
3
Good, so what's the value of \[7^{-3}\]
0.002915452.... Im not sure
\[7^{-3}=\frac 1 {7^3}\]
oh my gosh, i forgot. but then to solve that what do i have to do
so \[\log_7 {\frac 1 {343}}=\log_7 \frac{1}{7^3}=\log_7 7^{-3}\] Can you solve now?
-49?
Do you know how log is defined?
what do you mean?
\[y=\log_x a\] so what's a here?
i have no idea
This means that \[a=y^x\] so if you have \[2^3=4\] that means \[\log_2 8 =3\]
ok so thats like \[logB^7 = T\] and \[B^T = 7\]
7 should not be the power of B, but B = base here
then thats why I'm confused with this problem because thats exactly what the teacher wrote on the board
Your question is correct. I meant that log is defined as \[a=\log_b x=> b^a =x\]
the question says \[\log7 \frac{ 1 }{ 343 }\] but i dont understand what im supposed to do
If you have a question , find the value of \[\log_ b a \] We need to find the power b has to be raised to get a, here you need to find the power 7 has to be raised to get 1/343
wait. so the answer is -3?
yes sir
(ma'am) and THANK YOU :0)
can i ask one last question please?
post it as a new one
ok thank you
ummmmm, .... how do i post a new question?
close this and post a new one
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