Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

log7 1/343

OpenStudy (ash2326):

@BooBoo9512 Can you find the answer for this? \[7^x=343\] What power 7 has to be raised to get 343?

OpenStudy (anonymous):

3

OpenStudy (ash2326):

Good, so what's the value of \[7^{-3}\]

OpenStudy (anonymous):

0.002915452.... Im not sure

OpenStudy (ash2326):

\[7^{-3}=\frac 1 {7^3}\]

OpenStudy (anonymous):

oh my gosh, i forgot. but then to solve that what do i have to do

OpenStudy (ash2326):

so \[\log_7 {\frac 1 {343}}=\log_7 \frac{1}{7^3}=\log_7 7^{-3}\] Can you solve now?

OpenStudy (anonymous):

-49?

OpenStudy (ash2326):

Do you know how log is defined?

OpenStudy (anonymous):

what do you mean?

OpenStudy (ash2326):

\[y=\log_x a\] so what's a here?

OpenStudy (anonymous):

i have no idea

OpenStudy (ash2326):

This means that \[a=y^x\] so if you have \[2^3=4\] that means \[\log_2 8 =3\]

OpenStudy (anonymous):

ok so thats like \[logB^7 = T\] and \[B^T = 7\]

OpenStudy (ash2326):

7 should not be the power of B, but B = base here

OpenStudy (anonymous):

then thats why I'm confused with this problem because thats exactly what the teacher wrote on the board

OpenStudy (ash2326):

Your question is correct. I meant that log is defined as \[a=\log_b x=> b^a =x\]

OpenStudy (anonymous):

the question says \[\log7 \frac{ 1 }{ 343 }\] but i dont understand what im supposed to do

OpenStudy (ash2326):

If you have a question , find the value of \[\log_ b a \] We need to find the power b has to be raised to get a, here you need to find the power 7 has to be raised to get 1/343

OpenStudy (anonymous):

wait. so the answer is -3?

OpenStudy (ash2326):

yes sir

OpenStudy (anonymous):

(ma'am) and THANK YOU :0)

OpenStudy (anonymous):

can i ask one last question please?

OpenStudy (ash2326):

post it as a new one

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

ummmmm, .... how do i post a new question?

OpenStudy (ash2326):

close this and post a new one

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!