Question

suppose you throw a ball up with a starting velocity of 40 ft/sec. the ball is 7 ft high when it leaves your hand. after how many seconds will it hit the ground. (round to nearest tenth). use h=-16t^2+vt+c

Answer 1

idk

Answer 2

Hello, I'm a mushi master. You want to plug in the 40ft/sec into the vt

h = -16t^2 + 40t + 7 (because s = height, and it's 7 feet)

Now all you gotta do is take that equation and find the points where x = 0.

Answer 3

@Compassionate so i'd plug in 0 for the "T's"

Answer 4

Nope. You want to use the quadratic equation and find where x = 0.

The parabola will tell you when the ball hit the ground.

Answer 5

@Compassionate so i dont really think im following, sorry! but the answer i got was 7 but i think thats wrong

Answer 6

Did you learn about the quadratic equation in school yet?

Answer 7

i think so. pretty sure we did

Answer 8

Okay, so the equation h = -16x^2 + vt + s, is basically setting you up to use the quadratic equation.

IF you were to plug it into the quadratic equation and solve it, you'll get the time. Go ahead and do a quick Google Search, you'll understand.

Answer 9

It's really easy once you find out how to do it. You'll be able to do them on your own in no time.

Answer 10

Oh okay thank you very much!

Answer 11

If you need further assistance in understanding, I'm here for you, man.