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Mathematics 13 Online
OpenStudy (anonymous):

Can someone help me with this one? Find the derivative...

OpenStudy (anonymous):

\[f(x) = (\frac{ 2x+4 }{ x-4})^5\]

OpenStudy (anonymous):

Just started derivatives and quite lost

OpenStudy (ash2326):

You would need to use chain rule here \[\frac{d}{dx} (f(g(x)))=f'(g(x)\times g'(x)\] suppose we have \[\frac{d}{dx} ( 4x)^3= 3\times(4x)^2 \times \frac {d}{dx} (4x)\] \[3\times(4x)^2 \times 4 \] Do you get this?

OpenStudy (anonymous):

Iget the 3 x (4x)^2 but why x 4?

OpenStudy (ash2326):

that's the derivative of 4x,

OpenStudy (anonymous):

Ohh ok

OpenStudy (ash2326):

so you have to use the same procedure in your question. Only thing is it's a bit complex

OpenStudy (anonymous):

If I do it now on paper could you check my answer? Might take me a minute or two

OpenStudy (ash2326):

ok, sure

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