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Can someone help me with this one? Find the derivative...
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\[f(x) = (\frac{ 2x+4 }{ x-4})^5\]
Just started derivatives and quite lost
You would need to use chain rule here \[\frac{d}{dx} (f(g(x)))=f'(g(x)\times g'(x)\] suppose we have \[\frac{d}{dx} ( 4x)^3= 3\times(4x)^2 \times \frac {d}{dx} (4x)\] \[3\times(4x)^2 \times 4 \] Do you get this?
Iget the 3 x (4x)^2 but why x 4?
that's the derivative of 4x,
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Ohh ok
so you have to use the same procedure in your question. Only thing is it's a bit complex
If I do it now on paper could you check my answer? Might take me a minute or two
ok, sure
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