I have the answer can somone please check me..... If E(t) represents the energy consumed in a househole in watts/ month what are the units of
\[\int\limits_{a}^{b}E(t)dt\]
integration is summing up E* dt (energy * time) if E is in watts/month and time is measured in months , the units are watts/month * month which you can simplify
I think the answer is watts/month^2
is that correct
\[ \frac{watts}{month} \cdot month \]
or , if you like \[ \frac{watts}{month}\cdot \frac{months}{1} \]
right so then the answer is watts/month^2
if it were numbers, for example \[ \frac{4}{2} \cdot \frac{2}{1} \] what do you get ?
oh are you saying it is just watts is the answer
yes, it is just watts \[ \frac{watts}{months} \cdot months = watts \cdot \frac{months}{months} = watts \]
ok thanks I understnad now months get canceled out thanks
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