Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Can anyone please help? http://prntscr.com/11zddy

OpenStudy (mertsj):

Common denominator is the product of the two denominators. Write the two fractions with a common denominator and add the numerators.

OpenStudy (anonymous):

i tried merts and i got A

OpenStudy (mertsj):

How did the cos^2 get into the numerator?

OpenStudy (mertsj):

\[\frac{1-\sin \theta}{(1-\sin \theta)(1+\sin \theta)}+\frac{1+\sin \theta}{(1-\sin \theta)(1+\sin \theta)}=\] \[\frac{2}{1-\sin ^2\theta}=\frac{2}{\cos ^2\theta}\]

OpenStudy (anonymous):

Merts so than it will be A right

OpenStudy (mertsj):

Do you think that these are the same: 1. \[2\cos ^2\theta \] 2. \[\frac{2}{\cos ^2\theta}\]

OpenStudy (anonymous):

no:(

OpenStudy (mertsj):

Then how could it be A?

OpenStudy (mertsj):

I have clearly posted that the result is : \[\frac{2}{\cos ^2\theta}\]

OpenStudy (anonymous):

but it is not one of the options

OpenStudy (mertsj):

It is one of the options. What is it equivalent to?

OpenStudy (mertsj):

What is 1/cos x ?

OpenStudy (mertsj):

\[\frac{1}{\cos x}=\]

OpenStudy (anonymous):

sec theta

OpenStudy (anonymous):

so B

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

What is the simplified form of sin(x + p)?

OpenStudy (anonymous):

-sinx or sinx

OpenStudy (mertsj):

Do you mean: \[\sin (x+\pi)\]

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

@Mertsj

OpenStudy (anonymous):

i think it -sinx

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!