Question

What is the sum ?

Answer 1

Did you get a common denominator and try this?

Answer 2

I didnt do anything. its just a question

Answer 3

You need to multiply each fraction in:
\[\frac{1}{g+2}+\frac{3}{g+1}\]
By something so that that denominator, or bottom, matches. Then they can be added.

Answer 4

i dont know how to do that

Answer 5

It all goes back to how yuo add fractions.
\[\frac{1}{2}+\frac{1}{3}\]To add those, I need the lowest common multiple, or common denominator. The left has a 2 on the bottom, the right a 3, so I multiply the left by 3/3 and the right by 2/2 .\[\frac{1}{2}\cdot \frac{3}{3}+\frac{1}{3}\cdot \frac{2}{2}\implies \frac{3}{6}+\frac{2}{6}\]Now I can add them. What you are doing is the same process.

Answer 6

so what would it be ?

Answer 7

Well, what would you multiply each side by?

Answer 8

do you have to cross multiply ??

Answer 9

Sort of. You cross multiply the top. Then the bottom just becomes the multiples of both bottoms.

Answer 10

O.o what ?

Answer 11

So it becomes this:
\[\frac{1(g+1)}{(g+2)(g+1)}+\frac{3(g+2)}{(g+2)(g+1)}\]

Answer 12

that escalated .

Answer 13

Yes, but now it can be added!

Answer 14

?

Answer 15

Yes.

Answer 16

thts the correct answer ?

Answer 17

\[\frac{g+1}{(g+2)(g+1)}+\frac{3g+6)}{(g+2)(g+1)}\implies

\frac{g+1+3g+6}{(g+2)(g+1)}\implies

\frac{4g+7}{(g+2)(g+1)}\]

Answer 18

Thank you ♥

Answer 19

np. I hope you get how it works so they will be easier for you!

Answer 20

♥ okay :D