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Mathematics 11 Online
OpenStudy (anonymous):

Help http://prntscr.com/120ari can you tell me if my answers are right

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok sry for taking so long, got distracted # 1 and # 2 are correct checking the others

jimthompson5910 (jim_thompson5910):

the others are correct as well, nice work

OpenStudy (anonymous):

other questions now

OpenStudy (anonymous):

http://prntscr.com/120egd

jimthompson5910 (jim_thompson5910):

# 5 is correct

jimthompson5910 (jim_thompson5910):

for #6, you could say that each term is multiplied by -1/2 to get the next term but you basically have it

jimthompson5910 (jim_thompson5910):

the last term of 1/8 should be -1/8

OpenStudy (anonymous):

http://prntscr.com/120f70

jimthompson5910 (jim_thompson5910):

8pi/4 is 2pi

jimthompson5910 (jim_thompson5910):

and the first line is known as the zeros or roots

jimthompson5910 (jim_thompson5910):

it's not where theta is 0, its where the function is zero

jimthompson5910 (jim_thompson5910):

oh and i should have seen this, but 2pi isn't a root 7pi/4 is a root (so you're slightly off a bit)

OpenStudy (anonymous):

i just have to change the statetment

jimthompson5910 (jim_thompson5910):

yeah and that last root

jimthompson5910 (jim_thompson5910):

everything else is correct

OpenStudy (anonymous):

http://prntscr.com/120fcd

jimthompson5910 (jim_thompson5910):

8 is correct, even though it's probably a bit messy and it needs some parenthesis

jimthompson5910 (jim_thompson5910):

you have the right idea though

jimthompson5910 (jim_thompson5910):

and i'm not sure how you got #9, but it looks off

OpenStudy (anonymous):

i skipped one of the step becuase it was making the answer look messsy like q8

OpenStudy (anonymous):

http://prntscr.com/120gbp

jimthompson5910 (jim_thompson5910):

sin(90-A) is NOT sin(A) sin(90-A) is actually cos(A)

OpenStudy (anonymous):

and cos 90-A is sin A

jimthompson5910 (jim_thompson5910):

cos(90-A) should be sin(A)

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

you'll get cos(A)/sin(A) = cot(A)

OpenStudy (anonymous):

sorry mistyped

jimthompson5910 (jim_thompson5910):

thats ok

OpenStudy (anonymous):

http://prntscr.com/120h7o

jimthompson5910 (jim_thompson5910):

both are correct, i would add in there that in general if a*b^x has b < 1, then you have exponential decay but you don't have to since you pretty much got the correct answer

OpenStudy (anonymous):

http://prntscr.com/120i5j i need help with this one

jimthompson5910 (jim_thompson5910):

cos(2x) = cos(x+x) then use cos(A+B) = cos(A)cos(B) - sin(A)sin(B)

jimthompson5910 (jim_thompson5910):

oh and also use sin^2(x) = 1-cos^2(x)

OpenStudy (anonymous):

then

OpenStudy (anonymous):

have supposed theta as x

jimthompson5910 (jim_thompson5910):

i know, i used x because it's easier to type out

jimthompson5910 (jim_thompson5910):

but the identities are still the same (replace every x with theta)

OpenStudy (anonymous):

then?

jimthompson5910 (jim_thompson5910):

what do you mean

OpenStudy (anonymous):

sin^2(x) = 1-cos^2(x)

jimthompson5910 (jim_thompson5910):

yes what about it?

OpenStudy (anonymous):

is it where it ends

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