Mathematics
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OpenStudy (anonymous):
Help
http://prntscr.com/120ari
can you tell me if my answers are right
13 years ago
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OpenStudy (anonymous):
@jim_thompson5910
13 years ago
jimthompson5910 (jim_thompson5910):
ok sry for taking so long, got distracted
# 1 and # 2 are correct
checking the others
13 years ago
jimthompson5910 (jim_thompson5910):
the others are correct as well, nice work
13 years ago
OpenStudy (anonymous):
other questions now
13 years ago
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jimthompson5910 (jim_thompson5910):
# 5 is correct
13 years ago
jimthompson5910 (jim_thompson5910):
for #6, you could say that each term is multiplied by -1/2 to get the next term
but you basically have it
13 years ago
jimthompson5910 (jim_thompson5910):
the last term of 1/8 should be -1/8
13 years ago
jimthompson5910 (jim_thompson5910):
8pi/4 is 2pi
13 years ago
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jimthompson5910 (jim_thompson5910):
and the first line is known as the zeros or roots
13 years ago
jimthompson5910 (jim_thompson5910):
it's not where theta is 0, its where the function is zero
13 years ago
jimthompson5910 (jim_thompson5910):
oh and i should have seen this, but 2pi isn't a root
7pi/4 is a root (so you're slightly off a bit)
13 years ago
OpenStudy (anonymous):
i just have to change the statetment
13 years ago
jimthompson5910 (jim_thompson5910):
yeah and that last root
13 years ago
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jimthompson5910 (jim_thompson5910):
everything else is correct
13 years ago
jimthompson5910 (jim_thompson5910):
8 is correct, even though it's probably a bit messy and it needs some parenthesis
13 years ago
jimthompson5910 (jim_thompson5910):
you have the right idea though
13 years ago
jimthompson5910 (jim_thompson5910):
and i'm not sure how you got #9, but it looks off
13 years ago
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OpenStudy (anonymous):
i skipped one of the step becuase it was making the answer look messsy like q8
13 years ago
jimthompson5910 (jim_thompson5910):
sin(90-A) is NOT sin(A)
sin(90-A) is actually cos(A)
13 years ago
OpenStudy (anonymous):
and cos 90-A is sin A
13 years ago
jimthompson5910 (jim_thompson5910):
cos(90-A) should be sin(A)
13 years ago
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jimthompson5910 (jim_thompson5910):
yep
13 years ago
jimthompson5910 (jim_thompson5910):
you'll get cos(A)/sin(A) = cot(A)
13 years ago
OpenStudy (anonymous):
sorry mistyped
13 years ago
jimthompson5910 (jim_thompson5910):
thats ok
13 years ago
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jimthompson5910 (jim_thompson5910):
both are correct, i would add in there that in general if a*b^x has b < 1, then you have exponential decay
but you don't have to since you pretty much got the correct answer
13 years ago
jimthompson5910 (jim_thompson5910):
cos(2x) = cos(x+x)
then use
cos(A+B) = cos(A)cos(B) - sin(A)sin(B)
13 years ago
jimthompson5910 (jim_thompson5910):
oh and also use
sin^2(x) = 1-cos^2(x)
13 years ago
OpenStudy (anonymous):
then
13 years ago
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OpenStudy (anonymous):
have supposed theta as x
13 years ago
jimthompson5910 (jim_thompson5910):
i know, i used x because it's easier to type out
13 years ago
jimthompson5910 (jim_thompson5910):
but the identities are still the same (replace every x with theta)
13 years ago
OpenStudy (anonymous):
then?
13 years ago
jimthompson5910 (jim_thompson5910):
what do you mean
13 years ago
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OpenStudy (anonymous):
sin^2(x) = 1-cos^2(x)
13 years ago
jimthompson5910 (jim_thompson5910):
yes what about it?
13 years ago
OpenStudy (anonymous):
is it where it ends
13 years ago