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logbase2(x) +4logbase2(y)-3logbase2(z) can someone rewrite as a single logarithm logbase2 A please
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using the logarithmic rule that \( log_b\alpha^\beta \implies \beta*log_b\alpha \), convert the 2nd and 3rd terms
can you help me please i dont know how
well, look at what you have for 2nd and 3rd terms
4 and -3
not just the coefficients, the term itself, literals and all
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4logbase2(y)-3logbase2(z) 4logbase2(y)-3logbase2(z)
\( \beta*log_b\alpha \implies (4)log_2Y \ \&\ (-3)log_2Z \)
is that the solution
and the rules is \(\beta*log_b\alpha \implies log_b\alpha^\beta \)
no, is not the solution, you need to convert them first, to get the the solution
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ok thanks
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