Question

logbase2(x) +4logbase2(y)-3logbase2(z)

can someone rewrite as a single logarithm logbase2 A please

Answer 1

using the logarithmic rule that \(
log_b\alpha^\beta \implies \beta*log_b\alpha
\), convert the 2nd and 3rd terms

Answer 2

can you help me please i dont know how

Answer 3

well, look at what you have for 2nd and 3rd terms

Answer 4

4 and -3

Answer 5

not just the coefficients, the term itself, literals and all

Answer 6

4logbase2(y)-3logbase2(z)

4logbase2(y)-3logbase2(z)

Answer 7

\(
\beta*log_b\alpha \implies (4)log_2Y \ \&\ (-3)log_2Z
\)

Answer 8

is that the solution

Answer 9

and the rules is \(\beta*log_b\alpha \implies log_b\alpha^\beta \)

Answer 10

no, is not the solution, you need to convert them first, to get the the solution

Answer 11

ok thanks

Answer 12

http://www.adug.org.au/MathsCorner/LOGS1.GIF