How to integrate 1/(3-x)^(1/2)
@Kuroten87 Hi , \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \) Did you try substitution u= 3-x ?
I actually tried subbing the square root of 3-x and finding x, then subbing that
So x would equal 3-u^2 and dx = -2udu
ok, now try, u= 3-x (instead of sqrt (3-x))
Now I have negative integral of 1/(u^1/2)du
thats quite simple right ? can you do it ?
Maybe if I stare at it long enough. Thanks:)
lol......let me give you a hint : \(\large \dfrac{1}{x^n}=x^{-n}\) and you have standard integration formula for x^n dx
and welcome ^_^
Lol oh yeah... Basic stuff. My bad.
no problem :)
oh, and since you are new here, if you have any doubts browsing this site, you can ask me, or to an ambassador (with an encircled A before their name). Have fun learning with Open Study! :)
Cool! Thanks again!
Join our real-time social learning platform and learn together with your friends!