Question

y=2sqrtx-x find domain, horizontal &vertical asymptotes, symmetry, first derivative

Answer 1

\[y=2\sqrt{x}-x\]

Answer 2

helppppppppp plzzzz

Answer 3

\[2 \sqrt {x-x}\] is it like that?

Answer 4

i wrote it above

Answer 5

2\[2{\sqrt{x}}-x\]

Answer 6

Domain: x >= 0

Answer 7

ok i got that, no horizontal or vertical asymptotes right

Answer 8

?

Answer 9

no, no asymptotes as the domain can be 0 and any x greater than 0.

For DERIVATIVE you are going to use the subtraction law and the index law and rewrite it as follows

\[2x^\frac{ 1 }{ 2 }\]

Answer 10

waittttttttttttttttttt

Answer 11

can i tell u wat i got for the derivative

Answer 12

\[\frac{ d}{ dx }2x^\frac{ 1 }{ 2 } - \frac{ d }{ dx }2\]

Answer 13

is your derivative \[x^\frac{- 1 }{ 2 }\]

Answer 14

?

Answer 15

quick i need to go.

Answer 16

i got x^1/2 -1

Answer 17

u forgot derivative of x

Answer 18

its y=2√x -x

Answer 19

my bad, i replaced x by 2 in my equation.

Just change yours to have a NEGATIVE in the power. So NEGATIVE 1/2.

Answer 20

remember

derivative n.a^n-1

Answer 21

ok i got it

Answer 22

it must be x^-1/2 - 1

Answer 23

cheers