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Chemistry 22 Online
OpenStudy (anonymous):

A solution contains 10.0 grams of acetic acid (CH3COOH) in 125 grams of water. What is the mole fraction of acetic acid

OpenStudy (aaronq):

\[\chi _{Acetic acid}=\frac{ n _{Aceticacid} }{ n _{Aceticacid}+n _{water} }\]

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