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hartnn (hartnn):
:O
first just tell me what gets cancelled ?
OpenStudy (anonymous):
x+1, x+3
hartnn (hartnn):
sure, does 'x+3' really get cancelled ? and yes, x+1 gets cancelled.
OpenStudy (anonymous):
Oh no it doesn't. So then we're left with.. 2/x+3 x+2 = 1/x+3
hartnn (hartnn):
how is the numerator = 1 ?
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OpenStudy (anonymous):
Oh no no , it's just what's on the other side.
OpenStudy (anonymous):
Oh I meant x
hartnn (hartnn):
\(\large \dfrac{ 2\cancel{(x+1)} }{(x+3)(x+2) } \times \dfrac{1}{ \cancel{(x+1)}( {x+3})}=\dfrac{2}{(x+2)(x+3)^2}\)
is what remas and cannot be simplified, so the answer...
OpenStudy (anonymous):
Thank you so much again! I understand it so much better. One last problem? So sorry for wearing you out!
OpenStudy (anonymous):
The second equation now D: Haha . :) Then I'm done.
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hartnn (hartnn):
no problem :)
6x-18 =... ?
hartnn (hartnn):
x^2+2x-15 =... ?
hartnn (hartnn):
umm...(x+6)(x-3) for what ?
6x-18 = 6 (......?.....)
OpenStudy (anonymous):
6(x+3)
hartnn (hartnn):
6 (x+3) or 6 (x-3) ??
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OpenStudy (anonymous):
Ooh x-3 xD
hartnn (hartnn):
x^2+2x-15 =... ?
OpenStudy (anonymous):
Um.. I'm not sure? D:
OpenStudy (anonymous):
Oh wait.
OpenStudy (anonymous):
(x+5)(x-3)?
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hartnn (hartnn):
yes!
OpenStudy (anonymous):
Yay.
hartnn (hartnn):
what gets cancelled ?
OpenStudy (anonymous):
x-3
OpenStudy (anonymous):
x+5
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